In mathematics, a measure on a real vector space is said to be transverse to a given set if it assigns measure zero to every translate of that set, while assigning finite and positive (i.e. non-zero) measure to some compact set.
Let V be a real vector space together with a metric space structure with respect to which it is complete. A Borel measure ü is said to be transverse to a Borel-measurable subset S of V if
The first requirement ensures that, for example, the trivial measure is not considered to be a transverse measure.
As an example, take V to be the Euclidean plane R<sup>2</sup> with its usual Euclidean norm/metric structure. Define a measure ü on R<sup>2</sup> by setting ü(E) to be the one-dimensional Lebesgue measure of the intersection of E with the first coordinate axis:
An example of a compact set K with positive and finite ü-measure is K = B<sub>1</sub>(0), the closed unit ball about the origin, which has ü(K) = 2. Now take the set S to be the second coordinate axis. Any translate (v<sub>1</sub>, v<sub>2</sub>) + S of S will meet the first coordinate axis in precisely one point, (v<sub>1</sub>, 0). Since a single point has Lebesgue measure zero, ü((v<sub>1</sub>, v<sub>2</sub>) + S) = 0, and so ü is transverse to S.