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Transverse measure

In mathematics, a measure on a real vector space is said to be transverse to a given set if it assigns measure zero to every translate of that set, while assigning finite and positive (i.e. non-zero) measure to some compact set.

Definition

Let V be a real vector space together with a metric space structure with respect to which it is complete. A Borel measure μ is said to be transverse to a Borel-measurable subset S of V if

  • there exists a compact subset K of V with 0 < ÃŽÂ¼(K) < +∞; and
  • μ(v + S) = 0 for all v Ã¢ÂˆÂˆ V, where
:
is the translate of S by v.

The first requirement ensures that, for example, the trivial measure is not considered to be a transverse measure.

Example

As an example, take V to be the Euclidean plane R<sup>2</sup> with its usual Euclidean norm/metric structure. Define a measure μ on R<sup>2</sup> by setting μ(E) to be the one-dimensional Lebesgue measure of the intersection of E with the first coordinate axis:

An example of a compact set K with positive and finite μ-measure is K&nbsp;=&nbsp;B<sub>1</sub>(0), the closed unit ball about the origin, which has μ(K)&nbsp;=&nbsp;2. Now take the set S to be the second coordinate axis. Any translate (v<sub>1</sub>,&nbsp;v<sub>2</sub>)&nbsp;+&nbsp;S of S will meet the first coordinate axis in precisely one point, (v<sub>1</sub>,&nbsp;0). Since a single point has Lebesgue measure zero, μ((v<sub>1</sub>,&nbsp;v<sub>2</sub>)&nbsp;+&nbsp;S)&nbsp;=&nbsp;0, and so μ is transverse to S.

See also

References