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Sodium telluride

Sodium telluride is the chemical compound with the formula Na<sub>2</sub>Te. This salt is the conjugate base of the thermally unstable acid hydrogen telluride, but it is usually prepared by reduction of tellurium with sodium. Na<sub>2</sub>Te is a challenging material to handle because it is very sensitive to air. Air oxidizes it initially to polytellurides, which have the formula Na<sub>2</sub>Te<sub>x</sub> (x > 1), and ultimately Te metal. Samples of Na<sub>2</sub>Te, which are colourless when absolutely pure, generally appear purple or dark gray due to the effects of air oxidation.

Synthesis, structure, and solution properties

The synthesis is typically conducted using ammonia as the solvent.

Na<sub>2</sub>Te, like many related compounds with the formula M<sub>2</sub>X, adopts the antifluorite structure. Thus, in solid Na<sub>2</sub>Te each Te<sup>2−</sup> ion is surrounded by eight Na<sup>+</sup> ions and each Na<sup>+</sup> ion is surrounded by four Te<sup>2−</sup> ions.

Simple salts of the type M<sub>2</sub>X, where X is a monatomic anion, are not typically soluble in any solvent because they have a high lattice energy. Upon addition of water - even moist air - or treatment with alcohols, Te<sup>2−</sup> protonates:

Na<sub>2</sub>Te + H<sub>2</sub>O → NaHTe + NaOH

Because of this reaction, many processes attributed to Na<sub>2</sub>Te may involve NaHTe (CAS # 65312-92-7), which is more soluble and formed readily.

Applications in organic chemistry

Na<sub>2</sub>Te finds use in organic synthesis, both as a reagent for reductions and as a source of Te in the synthesis of organotellurium compounds. Aryl halides are substituted to diaryl tellurides, as illustrated by the synthesis of dinaphthyltelluride:

Na<sub>2</sub>Te + 2 C<sub>10</sub>H<sub>7</sub>I → (C<sub>10</sub>H<sub>7</sub>)<sub>2</sub>Te + 2 NaI

Na<sub>2</sub>Te reacts with 1,3-diynes to give the corresponding tellurophene, which are structurally analogous to thiophenes:

Na<sub>2</sub>Te + RC≡C-C≡CR + 2 H<sub>2</sub>O → TeC<sub>4</sub>R<sub>2</sub>H<sub>2</sub> + 2 NaOH

As a reducing agent, Na<sub>2</sub>Te converts nitro groups to amines and will cleave certain C-X bonds.

References