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Lutetium(III) hydroxide

Lutetium(III) hydroxide is an inorganic compound with the chemical formula Lu(OH)<sub>3</sub>.

Production

Reacting lutetium chloride and alkalis will first produce Lu(OH)<sub>2</sub>Cl, then it will become Lu(OH)<sub>2.5</sub>Cl<sub>0.5</sub>. Finally, the reaction will produce Lu(OH)<sub>3</sub>.

LuCl<sub>3</sub>+2 NaOH→Lu(OH)<sub>2</sub>Cl+2 NaCl
Lu(OH)<sub>2</sub>Cl+0.5 NaOH→Lu(OH)<sub>2.5</sub>Cl<sub>0.5</sub>+0.5 NaCl
Lu(OH)<sub>2.5</sub>Cl<sub>0.5</sub>+0.5 NaOH→Lu(OH)<sub>3</sub>+0.5 NaCl

Chemical properties

Lutetium(III) hydroxide can react with acid and form lutetium(III) salts：

Lu(OH)<sub>3</sub> + 3 H<sup>+</sup> → Lu<sup>3+</sup> + 3 H<sub>2</sub>O

While heating lutetium(III) hydroxide, it will produce LuO(OH), continued heating could produce Lu<sub>2</sub>O<sub>3</sub>.

References