ò-Hydride elimination is a reaction in which a metal-alkyl centre is converted into the corresponding metal-hydride-alkene. ò-Hydride elimination can also occur for many alkoxide complexes as well. The main requirements are that the alkyl group possess a C-H bond ò to the metal and that the metal be coordinatively unsaturated. Thus, metal-butyl complexes are susceptible to this reaction whereas metal-methyl complexes are not. The complex must have an empty (or vacant) site cis to the alkyl group for this reaction to occur. ò-Hydride elimination, which can be desirable or undesirable, affects the behavior of many organometallic complexes.
Moreover, for facile cleavage of the CâÂÂH bond, a d electron pair is needed for donation into the ÃÂ* orbital of the CâÂÂH bond. Thus, d<sup>0</sup> metals alkyls are generally more stable to ò-hydride elimination than d<sup>2</sup> and higher metal alkyls and may form isolable agostic complexes, even if an empty coordination site is available.
The Shell higher olefin process relies on ò-hydride elimination to produce ñ-olefins which are used to produce detergents.
ò-Hydride elimination interferes with the ZieglerâÂÂNatta polymerization, leading to decreased molecular weight. The production of branched polymers from ethylene relies on chain walking, a key step of which is ò-hydride elimination.
Nickel- and palladium-catalyzed couplings mainly focus on aryl-aryl couplings. Aryl-alkyl and especially alkyl-alkyl couplings are less successful because of ò-hydride elimination can lower the yield.
In Hydroformylation, ò-hydride elimination can act as a side reaction that influences product regioselectivity. For example, in the hydroformylation of open chain unsaturated ethers, it reverses the formation of branched metal-alkyl intermediates at high temperatures, leading to a greater yield of linear products.
ò-Hydride elimination is one step in the synthesis of some metal hydrides. For instance in the synthesis of RuHCl(CO)(PPh<sub>3</sub>)<sub>3</sub> from ruthenium trichloride, triphenylphosphine and 2-methoxyethanol, an intermediate alkoxide complex undergoes a ò-hydride elimination to form the hydride ligand and the pi-bonded aldehyde which then is later converted into the carbonyl (carbon monoxide) ligand.
ò-Hydride elimination transforms a metal-alkyl complex into a metal-hydrido-alkene complex. Starting with an unsaturated complex, the transformation proceeds in stages: 1) Dissociation of a ligand from a metal alkyl complex, yielding a coordinatively unsaturated derivative. 2) Alignment of the beta hydrogen. In this step, a vacant site on the metal forms an agostic complex by binding a C-H bond of the alkyl (or alkoxide). 3) Hydride Transfer/Alkene Formation. In this step, the M-H bond forms concomitant with cleavage of a C-H bond and the development of a double bond in what was once an alkyl (or alkoxide) ligand. The resulting metal hydride can eliminate the alkene ligand. The transition state for this ò-hydride elimination involves a 4-membered ring.
Especially for Pt(II) complexes, ò-hydride eliminations may occur without the dissociation of an ancillary ligand. This was suggested primarily based on the observed order of the L-type ligand in the rate law derived from kinetic studies. This mechanism appears to be operative for the minority of reactions studied.
Relative to an arbitrary reference complex, ò-hydride elimination is faster in a complex with the following characteristics:
Several strategies exist for avoiding ò-hydride elimination. The most common strategy is to employ alkyl ligands that lack hydrogen atoms at the ò position. Common substituents include methyl and neopentyl. ò-Hydride elimination is also inhibited when the reaction would produce a strained alkene. This situation is illustrated by the stability of metal complexes containing norbornyl ligands, where the ò-hydride elimination product would violate Bredt's rule.
Dissociation-induced ò-hydride eliminations.
ò-Hydride elimination involving metal alkoxide and amido complexes.