Zirconium(III) bromide is an inorganic compound with the formula ZrBr<sub>3</sub>.
Almost all the trihalides of titanium, zirconium and hafnium can be prepared by the high-temperature reduction of the corresponding tetrahalide with the metal. Incomplete reaction and contamination of the product with excess metal often occurs.
Zirconium(III) bromide can thus be prepared from zirconium(IV) bromide and zirconium foil.
Alternatively, zirconium(III) bromide crystallises from a solution of zirconium(III) in aluminium tribromide. The solution is prepared by reducing a eutectic solution of ZrBr<sub>4</sub> in liquid AlBr<sub>3</sub> at a temperature of 230âÂÂ300 ðC with metallic zirconium or aluminium.
Zirconium(III) bromide has a lower magnetic moment than is expected for the d<sup>1</sup> metal ion Zr<sup>3+</sup>, indicating non-negligible Zr-Zr bonding.
The crystal structure of zirconium(III) bromide is based on hexagonal close packing of bromide ions with one third of the octahedral interstices occupied by Zr<sup>3+</sup> ions. The structure consists of parallel chains of face-sharing {ZrBr<sub>6</sub>} octahedra with equally spaced metal atoms. There is some elongation of the octahedra along the metal-metal axis, partly due to metal-metal repulsion. ZrCl<sub>3</sub>, ZrBr<sub>3</sub> and ZrI<sub>3</sub> all adopt the ò-TiCl<sub>3</sub> structure, but the elongation of octahedra is most pronounced in the chloride, moderate in the bromide and negligible in the iodide.